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General Climbing Discussion

Topic Date User

tyrolean traverse 17-Nov-2011 At 4:00:28 PM lacto

Message

On 17/11/2011 stealth wrote:
>Tyrolean traverses are a vector pull situation. That is, you are applying
>force to 2 anchors 90 degrees to the direction of pull. This means you
>are applying several times more than your 80+kg static mass.
>
>Check this website. It has an awesome simulator:
>
>http://www.tagsafety.com/library6.asp
>
>At zero degree rope angle for your weight, you are applying 28kN to each
>anchor.

Actually at 0 degrees the load is infinite ! at 1 degree it would be (1000/2) /sin 1degree N which is 28.6kN
If your rope is 20 metres between tree then 1 degree is sag of 17 cm and an elongation of 1.4 mm or stretch of 0.14% which is definitely not dynamic rope. All simple trig and pythagorus . At those type of loads the trees will be moving under load increasing the sagging but thereby reducing the loads .